(x-2)/(x^2+2)=2

Solution for (x-2)/(x^2+2)=2 equation:

(x-2)/(x^2+2)=2

We move all terms to the left:

(x-2)/(x^2+2)-(2)=0


Domain of the equation: (x^2+2)!=0

We move all terms containing x to the left, all other terms to the right

x^2!=-2

x^2!=-2/

x^2!=√-1/0

x!=NAN

x∈R


We multiply all the terms by the denominator


(x-2)-2*(x^2+2)=0

We multiply parentheses

-2x^2+(x-2)-4=0

We get rid of parentheses

-2x^2+x-2-4=0

We add all the numbers together, and all the variables

-2x^2+x-6=0

a = -2; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-2)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation